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0=x^2-2x-264
We move all terms to the left:
0-(x^2-2x-264)=0
We add all the numbers together, and all the variables
-(x^2-2x-264)=0
We get rid of parentheses
-x^2+2x+264=0
We add all the numbers together, and all the variables
-1x^2+2x+264=0
a = -1; b = 2; c = +264;
Δ = b2-4ac
Δ = 22-4·(-1)·264
Δ = 1060
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1060}=\sqrt{4*265}=\sqrt{4}*\sqrt{265}=2\sqrt{265}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{265}}{2*-1}=\frac{-2-2\sqrt{265}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{265}}{2*-1}=\frac{-2+2\sqrt{265}}{-2} $
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